# ch2o bond length

OH 1 The measurement will be displayed in nanometers (nm). In-Lab Question C1. The character of a bond is related to the difference in the electronegativities of the bonded atoms. First of all, what are the hybridisation schemes? measurement disappear, re-measure the angle in the same way.
T/F: resonance structures are different possible structures for the same species that interconvert rapidly. rather the true structure is a single structure that is an average of all possible resonance forms. Select the correct statement. To make the

1 bond angle) 2 sp H2O tetrahedral degrees. The formation of ionic compound involves the transfer of electrons. Active 5 years ago.
An sp orbital has more "s character" than an sp$^2$ orbital (you can think of an sp orbital as 50% s character, 50% p character and an sp$^2$ orbital as 33% s character, 67% p character), therefore the electron density in an sp orbital is on average closer to the nucleus of the C atom than in an sp$^2$ orbital, leading to a shorter $\sigma$ bond length. The measurement will be displayed in degrees.

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The hybridization will be sp2 because the s orbital can only form 1 bond and the 2 p orbitals must be combined with the s orbital to allow for 3 bonds to be made by the central atom. In CH$_2$O, the C atom is sp$^2$ hybridized, meaning the C$=$O bond is formed by an overlapping sp$^2$ orbital from C and an sp$^2$ orbital from O (since O is sp$^2$ hybridized) for the $\sigma$ bond and an overlapping p orbital from C and a p orbital from O for the $\pi$ bond.