My only proposal is that the $\ce{HgSO4}$ adds first, in an anti-Markovnikov fashion, forcing an $\ce{H}$ from $\ce{H3O+}$ to add on the terminal carbon and thus water to add to the other side. show that no redox has occurred.

To enable Verizon Media and our partners to process your personal data select 'I agree', or select 'Manage settings' for more information and to manage your choices. \(\ce{HClO + H2S -> H3O^+ + Cl^{–} + S}\)

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Missed the LibreFest? Read MSDS (Material Safety Data Sheets) before you do this experiment. Some elements almost always have the same oxidation states in their compounds: The reaction with ethene Alkenes react with concentrated sulphuric acid in the cold to produce alkyl hydrogensulphates. Just like in the analogous reaction of alkenes, the new proton goes to the least substituted position, to give the most substituted carbocation. The goal of the problem is to choose the reagent that will result in a particular ketone. Find out more about how we use your information in our Privacy Policy and Cookie Policy. Why is Soulknife's second attack not Two-Weapon Fighting? A is [1,1'-bicyclopentyl]-1-ol, B is cyclopentylidenecyclopentane, and C is 1-cyclopentylcyclopentene. It is found that at 0 K and with zero-point energy included, the proton transfer is endothermic by 3.4 kcal/mol.

Ethene reacts to give ethyl hydrogensulphate. This is done by assigning oxidation numbers to each atom before and after the reaction. The sum of the oxidation states of all the atoms in an ion is equal to the charge on the ion.


Counting the number of electrons transferred is an inefficient and time-consuming way of determining oxidation states.These rules provide a simpler method: Hydrogen in the metal hydrides: Metal hydrides include compounds like sodium hydride, NaH. This is an acid-base reaction because a proton, but no electrons, has been transferred. Even though this may (and indeed should) make you suspicious of the validity of oxidation numbers, they are undoubtedly a useful tool for spotting electron-transfer processes. Because Group 1 metals always have an oxidation state of +1 in their compounds, it follows that the hydrogen must have an oxidation state of -1 (+1 -1 = 0). Making statements based on opinion; back them up with references or personal experience.

Some strange moves in Polgar vs Najer (2009). How does the UK manage to transition leadership so quickly compared to the USA? The reaction is H2SO4 + 2KOH = K2SO4 + 2H2O It resembles a double displacement reaction. site design / logo © 2020 Stack Exchange Inc; user contributions licensed under cc by-sa.

Here the hydrogen exists as a hydride ion, H-. \(\ce{2MnO4^{–} + 5SO2 + 6H2O -> 5SO4^{2–} + 2Mn^{2+} + 4H3O^{+}}\), \(\ce{NH4^+ + PO4^{3–} -> NH3 + PO4^{2–}}\), \(\ce{HClO + H2S -> H3O^+ + Cl^{–} + S}\).

Notice how it is balanced so that there are the same number of each type of atom on both sides of the reaction. H 2 SO 4 /HgSO 4 are used to catalyze the hydrolysis becauase alkyne and water reaction occurs very slowly. The sum of the oxidation states of all the atoms or ions in a neutral compound is zero.

Could someone show how this mechanism works or explain a bit about how the presence of $\ce{HgSO4}$ and $\ce{H2SO4}$ affect the reaction? Are Members of Scottish and Welsh Parliaments called "Honourable"?

The reaction is a redox process. Chemistry Stack Exchange is a question and answer site for scientists, academics, teachers, and students in the field of chemistry.

My only proposal is that the $\ce{HgSO4}$ adds first, in an anti-Markovnikov fashion, forcing an $\ce{H}$ from $\ce{H3O+}$ to add on the terminal carbon and thus water to add to the other side. Instead, there are covalent bonds and electron-pair sharing between nitrogen and oxygen in both species, and nitrogen has certainly not lost its valence electrons entirely to oxygen.

In order to be able to recognize redox reactions, we need a method for keeping a careful account of all the electrons. The sp2 (vinyl) carbocation shown in the first mechanism is less stable than sp3 carbocations, so we would expect rearrangement to be an issue. Identify the redox reactions and the reducing and oxidizing agents from the following:

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